Posted by Ennead/Ogdoad/Ra breeding
Ecaeris|Pistachio
Lace Enjoyer (#470461)

Magnificent
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Posted on
2024-05-06 14:35:11
I keep running across people whose stud rules have those three bases listed as opposing factors for each other, so that breeding two together yields the third, like:
Ennead x Ogdoad = Ra
etc.

But, the wiki has them listed as factors that are grouped on the same side. My interpretation is that breeding any of the three to a base that corresponds to one of them has a chance of yielding the corresponding one, like:

[Ennead or Ra or Ogdoad] x [Deshret or Nefer or Wepwawet] = Ra
[En/Ra/Og trio] x [any other Ennead factor] = Ennead

With the caveat that two of the trio bred together can yield either one (but not the third), like:

Ra x Ennead = [Ra or Ennead]

Am I right? Or am I throwing my beetles into the void breeding an Ubaste to a Ra in hopes of an Ogdoad?



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Magnituda|G2 Torn
Orchid,14BO (#200075)


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Posted on
2024-05-07 04:43:25
You're not unfortunately. The stud rules you're refering to are correct

Only the pairing of
Ennead x Ogdoad
Ennead x Ra
Ogdoad x Ra

Can throw the third combo.

As for the Wiki - it's confusing but if you look closer you'll see that:
If two bases have "x" between them then they're the factors.

Ennead, Ogdoad & Ra have "xs" between them. And it's true that they're on the opposing side to app factors but there is a LINE between and not "x" so that means that it's either the top bases OR bottom bases bred together 😊

And Ubaste isn't even a factor to any of those. Ubaste is a part of earlier set of combos - so Gilded, Rose Gold, Sphinx.



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Edited on 07/05/24 @ 04:48:50 by Magnituda [G7 high BO Orchid] (#200075)







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