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Posted by | Breeding Genetics |
Crash (#233001) Bone Collector View Forum Posts Posted on 2021-04-29 07:28:52 |
Hi quick question, hopefully. Are children of mutties more likely to produce a muttie of that type? This would only be for inheritable mutations obviously. I like messing with genetics in games and was just wondering if this was a thing. Like this type of thing Non mut father |--------------->Non mut Pie-mother | |-------------->Pie? Non mut? Pie-father | |--------------->Non-mut Non-mut mother 0 players like this post! Like? |
🦜 Jenday 🦜 [Folklore] (#175593) Wanderer View Forum Posts Posted on 2021-04-29 07:55:15 |
Mutations don't skip a generation in lioden and theres no recessive traits that can hide in a lineage. This means the only way for a mutation to pass if it comes directly from a parent! You can check the Wiki for a full list of all passable mutations 0 players like this post! Like? |
Mad Hyena (#29080)
Special Snowflake View Forum Posts Posted on 2021-04-29 08:06:55 |
No, its not! There is no complex genetics like that. There's a mutation on parent, and there's a %s chance it will pass from that parent - that's all. Non-mutated cubs are the "fails" and have NO chance to pass grandparents' mutation to their own cubs, at all. If a lion has no passable mutation, its cubs have no chance to be mutated. Non-passable random mutations also do not follow any "genetics", its a simple "0,0X% a cub will have a mutation appear randomly". It does not involve any grandparents/genes, just a RNG roll if a cub gets a random mutation or not. 0 players like this post! Like? Edited on 29/04/21 @ 08:09:51 by Mad Hyena (#29080) |
Crash (#233001)
Bone Collector View Forum Posts Posted on 2021-04-29 07:53:43 |
Ok! Thank you^^ ok the example didn't work, so like this non-muttie(A1) + muttie(A1) = non-muttie(a1) non-muttie(B2) + muttie(B2) = non-muttie(b1) non-muttie(a1) + non-muttie(b1) = muttie(c1)? 0 players like this post! Like? Edited on 29/04/21 @ 07:57:36 by Crash (#233001) |
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